Trygonometria, zadanie nr 1781
ostatnie wiadomo艣ci | regulamin | latex
| Autor | Zadanie / Rozwi膮zanie |
emilkaa2345 post贸w: 25 |  2012-04-27 22:30:02rozwi膮偶 tr贸jk膮t prostok膮tny:a)a=10 b=20 b)a=15 c=17 c) alfa=30 stopni c=20 |
aididas post贸w: 279 | 2012-04-27 23:23:33 a)$c^{2}=a^{2}+b^{2}$ $c^{2}=10^{2}+20^{2}$ $c^{2}=100+400$ $c^{2}=500$ $c=\sqrt{500}$ $c=\sqrt{100}\sqrt{5}$ $c=10\sqrt{5}$ |
aididas post贸w: 279 | 2012-04-27 23:28:26 $b)b^{2}=c^{2}-a^{2}$ $b^{2}=17^{2}-15^{2}$ $b^{2}=289-225$ $b^{2}=64$ $b=8$ |
aididas post贸w: 279 | 2012-04-27 23:57:27 c)$sin\alpha=\frac{a}{c}$ $sin30^{\circ}=\frac{a}{20}$ $\frac{1}{2}=\frac{a}{20}$ $a=10$ $cos\alpha=\frac{b}{c}$ $cos30^{\circ}=\frac{b}{20}$ $\frac{\sqrt{3}}{2}=\frac{b}{20}$ $b=\frac{20\sqrt{3}}{2}$ $b=10\sqrt{3}$ |
abcdefgh post贸w: 1255 | 2012-04-28 20:30:43 a) a=10 b=20 c=10$\sqrt{5}$ cos$\alpha$=$\frac{20}{10\sqrt{5}}$ cos$\alpha$=$\frac{2\sqrt{5}}{5}$ cos$\alpha \approx$0,894427 cos$\alpha$=27 $\alpha$=27 $\beta$=63 b)a=15 b=8 c=17 $cos\alpha$=8/17 cos$\alpha$=0,4705 $\alpha=62$ i $\beta$=28 c)beta=60 |
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