Pierwiastki, pot臋gi, logarytmy, zadanie nr 3503
ostatnie wiadomo艣ci | regulamin | latex
| Autor | Zadanie / Rozwi膮zanie |
qlfon post贸w: 17 |  2013-11-22 11:12:21a. $ 3^{51} : 9^{24} =$ b. $(2^{2})^{3} * 5^{6} = $ c. $\frac{25: {(\frac{1}{5}})^{-7}}{25^{9}} =$ d. $\frac{2^{15}*9^3}{6^{15}} = $ |
mimi post贸w: 171 | 2013-11-22 17:02:38 a.) $3^{51} : 9^{24} = \frac{3^{51}}{(3^{2})^{24}} = \frac{3^{51}}{3^{48}} = 3^{3} = 27$ |
mimi post贸w: 171 | 2013-11-22 17:03:36 b.) $(2^{2})^{3} \cdot 5^{6} = 2^{6} \cdot 5^{6} = 10^{6} = 1000000$ |
mimi post贸w: 171 | 2013-11-22 17:07:20 c.)$ \frac{25 : (\frac{1}{5})^{-7}}{25^{9}} = \frac{5^{2} : 5^{7}}{5^{18}} = 5^{-23} = \frac{1}{5^{23}} = \frac{1}{11920928955078125}$ |
mimi post贸w: 171 | 2013-11-22 17:10:19 d.) $\frac{2^{15} \cdot 9^{3}}{6^{15}} = \frac{2^{15} \cdot 3^{6}}{2^{15} \cdot 3^{15}} = \frac{1}{3^9} = \frac{1}{19683}$ |
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