Liczby rzeczywiste, zadanie nr 4873
ostatnie wiadomo艣ci | regulamin | latex
| Autor | Zadanie / Rozwi膮zanie |
fazi post贸w: 26 |  2015-01-08 11:12:46prosz臋 o rozpisanie a)$\lim_{x \to \infty}\frac{2n^{2}+5}{n^{2}}$ b)$\lim_{x \to \infty}\frac{7n^{2}-5}{n^{2}-1}$ c)$\lim_{x \to \infty}\frac{3-n-n^{2}}{n^{2}+3n}$ d)$\lim_{x \to \infty}\frac{n^{2}+n-2}{n^{3}-n+1}$ e)$\lim_{x \to \infty}\frac{n^{2}+3n-1}{n+1}$ f)$\lim_{x \to \infty}\frac{2n^{3}+n^{2}+3}{n^{2}+4}$ |
irena post贸w: 2636 | 2015-01-08 12:40:29 $\frac{2n^2+5}{n^2}=2+\frac{5}{n^2}\to2$ |
irena post贸w: 2636 | 2015-01-08 12:41:14 $\frac{7n^2-5}{n^2-1}=\frac{7-\frac{5}{n^2}}{1-\frac{1}{n^2}}\to7$ |
irena post贸w: 2636 | 2015-01-08 12:42:05 $\frac{3-n-n^2}{n^2+3n}\to\frac{-1}{1}=-1$ |
irena post贸w: 2636 | 2015-01-08 12:43:36 $\frac{n^2+n-2}{n^3-n+1}=\frac{\frac{1}{n}+\frac{1}{n^2}-\frac{2}{n^3}}{1-\frac{1}{n^2}+\frac{1}{n^3}}\to0$ |
irena post贸w: 2636 | 2015-01-08 12:44:38 $\frac{n^2+3n-1}{n+1}=\frac{n+3-\frac{1}{n}}{1+\frac{1}{n}}\to\infty$ |
irena post贸w: 2636 | 2015-01-08 12:46:10 $\frac{2n^3+n^2+3}{n^2+4}=\frac{2n+1+\frac{3}{n^2}}{1+\frac{4}{n^2}}\to\infty$ |
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